ARPACKC 调用问题
 

请问调用时选项iparam(7)=mode的定义是否与FORTRAN 中的已经不同了
原fortran中
c Mode 1: A*x = lambda*x, A symmetric
c ===> OP = A and B = I.
c
c Mode 2: A*x = lambda*M*x, A symmetric, M symmetric positive definite
c ===> OP = inv[M]*A and B = M.
c ===> (If M can be factored see remark 3 below)
c
c Mode 3: K*x = lambda*M*x, K symmetric, M symmetric positive semi-definite
c ===> OP = (inv[K - sigma*M])*M and B = M.
c ===> Shift-and-Invert mode
c
c Mode 4: K*x = lambda*KG*x, K symmetric positive semi-definite,
c KG symmetric indefinite
c ===> OP = (inv[K - sigma*KG])*K and B = K.
c ===> Buckling mode
c
c Mode 5: A*x = lambda*M*x, A symmetric, M symmetric positive semi-definite
c ===> OP = inv[A - sigma*M]*[A + sigma*M] and B = M.
c ===> Cayley transformed mode
从matlab 函数eigs中可以看出原fortran mode=2,mode=1的情况都对应mode=1了,请问新的模式对应关系是什么样的（全部）