可以对以下循环进行矢量化吗？
 

我有一个执行以下功能的for循环：

取M x 8矩阵，然后：
[LIST=1][*]将其拆分为大小为512个元素的块（意味着X乘以矩阵的8 == 512，元素数量可以为128,256,512,1024,2048）[*]将块重塑为1 x 512（元素数）矩阵。[*]取矩阵的最后1/4放在前面，
例如Data = [Data(1,385:512),Data(1,1:384)];[/LIST]以下是我的代码：

for i = 1 : NumOfBlock if i == 1 Header = tempHeader(1:RowNeeded,:); Header = reshape(Header,1,BlockSize); %BS Header = [Header(1,385:512),Header(1,1:384)]; %CP Data = tempData(1:RowNeeded,:); Data = reshape(Data,1,BlockSize); %BS Data = [Data(1,385:512),Data(1,1:384)]; %CP start = RowNeeded + 1; end1 = RowNeeded * 2; else temp = tempData(start:end1,:); temp = reshape(temp,1,BlockSize); %BS temp = [temp(1,385:512),temp(1,1:384)]; %CP Data = [Data, temp]; end if i 1 temp = tempHeader(start:end1,:); temp = reshape(temp,1,BlockSize); %BS temp = [temp(1,385:512),temp(1,1:384)]; %CP Header = [Header, temp]; end start = end1 + 1; end1=end1 + RowNeeded; end 使用500万个元素运行此循环将花费超过1个小时的时间。我需要它尽快（以秒为单位）。这个循环能被向量化吗？



[B]回答：[/B]

我再次感谢阿姆罗（Amro）给我一个解决问题的想法。抱歉，我在问题中没有明确表示自己。

这是我对问题的解决方案：

%#BS CDMA, Block size 128,512,1024,2048 BlockSize = 512; RowNeeded = BlockSize / 8; TotalRows = size(tempData); TotalRows = TotalRows(1,1); NumOfBlock = TotalRows / RowNeeded; CPSize = BlockSize / 4; %#spilt into blocks Header = reshape(tempHeader',[RowNeeded,8, 128]); Data = reshape(tempData',[RowNeeded,8, NumOfBlock]); clear tempData tempHeader; %#block spread & cyclic prefix K = zeros([1,BlockSize,128],'single'); L = zeros([1,BlockSize,NumOfBlock],'single'); for i = 1:NumOfBlock if i