矩阵加法跳过NaN值
 

我想在跳过[I]NaN[/I]值的同时对矩阵进行元素明智加法。 MATLAB和Octave具有[I]nansum[/I] ，但它在矩阵内按列进行加法运算。

让：

a = NaN * zeros(3) b = ones(3)
我想要：

c = nan+(a, b) 和

c = b
和：

d = nan+(a,a) 和

d = a
回答：
如果沿第n + 1个维度对nd数组进行分类，则仍然可以使用nansum。

对于2D

% commands de-nested for readability. You can do this with a single line, of course tmp = cat(3,a,b); c = nansum(tmp,3); 一般情况

function out = nansumByElement(A,B) %NANSUMBYELEMENT performs an element-wise nansum on the nD arrays A and B % A and B have to have the same size % test input if nargin < 2 || isempty(A) || isempty(B) || ndims(A)~=ndims(B) || ~all(size(A)==size(B)) error('please pass two non-empty arrays of the same size to nansumByElement') end % calculate output nd = ndims(A); % get number of dimensions % catenate and sum along n+1st dimension out = nansum(cat(nd+1,A,B),nd+1);

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