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[求助]ode45和循环问题
function dy = 0518(t,y)
dy = zeros(8,1); kprisclb2=0.004; ksclb2=0.01; kpridclb2=0.0125; kdclb2=0.5; kas2=10; kds2=0.01; kpriamcm1=0.01; kamcm1=2; kimcm1=0.2; ksclb5=0.01; kpridclb5=0.02; kdclb5=0.05; kas5=10; kds5=0.01; kprissic1=0.02; kssic1=1; kdsic1=2; kpridsic1=0.3; kpri2dsic1=2; kaswi5=0.01; kpriaswi5=1; kiswi5=0.01; kpriiswi5=1; jswi5=0.1; kscdh1=0.02; kdcdh1=0.02; cdc14=0.02; apc=1; kprisclb5=0; dy(1)=kprisclb2+ksclb2*y(7)-y(1)*(kpridclb2+kdclb2*y(6)*apc); dy(2)=kprisclb5-y(2)*(kpridclb5+kdclb5*y(6)*apc); dy(3)=kprissic1+kssic1*y(8)-y(3)*(kpridsic1+kpri2dsic1*(y(2)-y(5))+kdsic1*(y(1)-y(4))); dy(4)=kas2*(y(1)-y(4))*(y(3)-y(4)-y(5))-kds2*y(4)-((kpridclb2+kdclb2*y(6)*apc)+(kpridsic1+kpri2dsic1*(y(2)-y(5))+kdsic1*(y(1)-y(4))))*y(4); dy(5)=kas5*(y(2)-y(5))*(y(3)-y(4)-y(5))-kds5*y(5)-((kpridclb5+kdclb5*y(6)*apc)+(kpridsic1+kpri2dsic1*(y(2)-y(5))+kdsic1*(y(1)-y(4))))*y(5); dy(6)=kscdh1-kdcdh1*y(6); dy(7)=(1-y(7))*(kpriamcm1+kamcm1*y(2))-kimcm1*y(7); dy(8)=(kaswi5+kpriaswi5*cdc14)*(1-y(8))/(jswi5+1-y(8))-(kiswi5+kpriiswi5*(y(1)-y(4)))*y(8)/(jswi5+y(8)); 如果我想在自变量t执行到50次时,调整参数,譬如把参数“apc”调整为0.02,请问高手指点! |
所有时间均为北京时间。现在的时间是 06:32。 |
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