poster
2019-12-10, 20:48
如何从法向矢量和一个点在matlab或matplotlib中绘制平面？
回答：
对于Matlab：
point = [1,2,3]; normal = [1,1,2]; %# a plane is a*x+b*y+c*z+d=0 %# [a,b,c] is the normal. Thus, we have to calculate %# d and we're set d = -point*normal'; %'# dot product for less typing %# create x,y [xx,yy]=ndgrid(1:10,1:10); %# calculate corresponding z z = (-normal(1)*xx - normal(2)*yy - d)/normal(3); %# plot the surface figure surf(xx,yy,z) https://i.stack.imgur.com/E80Ov.png
注意：仅当normal（3）不为0时，此解决方案才有效。如果平面平行于z轴，则可以旋转尺寸以保持相同的方法：
z = (-normal(3)*xx - normal(1)*yy - d)/normal(2); %% assuming normal(3)==0 and normal(2)~=0 %% plot the surface figure surf(xx,yy,z) %% label the axis to avoid confusion xlabel('z') ylabel('x') zlabel('y')
更多&回答... (https://stackoverflow.com/questions/3461869)
回答：
对于Matlab：
point = [1,2,3]; normal = [1,1,2]; %# a plane is a*x+b*y+c*z+d=0 %# [a,b,c] is the normal. Thus, we have to calculate %# d and we're set d = -point*normal'; %'# dot product for less typing %# create x,y [xx,yy]=ndgrid(1:10,1:10); %# calculate corresponding z z = (-normal(1)*xx - normal(2)*yy - d)/normal(3); %# plot the surface figure surf(xx,yy,z) https://i.stack.imgur.com/E80Ov.png
注意：仅当normal（3）不为0时，此解决方案才有效。如果平面平行于z轴，则可以旋转尺寸以保持相同的方法：
z = (-normal(3)*xx - normal(1)*yy - d)/normal(2); %% assuming normal(3)==0 and normal(2)~=0 %% plot the surface figure surf(xx,yy,z) %% label the axis to avoid confusion xlabel('z') ylabel('x') zlabel('y')
更多&回答... (https://stackoverflow.com/questions/3461869)