如何在MATLAB中的.txt文件中保存数据

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我有3个txt文件s1.txt, s2.txt, s3.txt 。每个文件都具有相同的格式和数据数量。我只希望将3个文件中的每个第二列合并为一个文件。在合并数据之前，我根据第一列对其进行了排序：

未排序的文件：s1.txt s2.txt s3.txt

1 23 2 33 3 22 4 32 4 32 2 11 5 22 1 10 5 28 2 55 8 11 7 11 排序文件：s1.txt s2.txt s3.txt

1 23 1 10 2 11 2 55 2 33 3 22 4 32 4 32 5 28 5 22 8 11 7 11 这是我到目前为止的代码：

BaseFile ='s' n=3 fid=fopen('RT.txt','w'); for i=1:n %Open each file consecutively d(i)=fopen([BaseFile num2str(i)'.txt']); %read data from file A=textscan(d(i),'%f%f') a=A{1} b=A{2} ab=[a,b]; %sort the data according to the 1st column B=sortrows(ab,1); %delete the 1st column after being sorted B(:,1)=[] %write to a new file fprintf(fid,'%d\n',B'); %close (d(i)); end fclose(fid); 如何以这种格式在新的txt文件中获取输出？

23 10 11 55 33 22 32 32 28 22 11 11 而不是这种格式？

23 55 32 22 10 33 32 11 11 22 28 11

回答：

首先创建输出矩阵，然后将其写入文件。

这是新代码：

BaseFile ='s'; n=3; for i=1:n % it's not recommended to use i or j as variables, since they used in complex math, but I'll leave it up to you % Open each file consecutively d=fopen([BaseFile num2str(i) '.txt']); % read data from file A=textscan(d,'%f%f', 'CollectOutput',1); % sort the data according to the 1st column B=sortrows(A{:},1); % Instead of deleting a column create new matrix if(i==1) C = zeros(size(B,1),n); end % Check input file and save the 2nd column if size(B,1) ~= size(C,1) error('Input files have different number of rows'); end C(:,i) = B(:,2); % don't write yet fclose (d); end % write to a new file fid=fopen('RT.txt','w'); for k=1:size(C,1) fprintf(fid, [repmat('%d\t',1,n-1) '%d\n'], C(k,:)); end fclose(fid); 编辑：实际上只写数字到一个文件，您不需要FPRINTF。使用DLMWRITE代替：

dlmwrite('RT.txt',C,'\t')

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