[MATLAB数学相关] 一元方程求多解 with complex number - MATLAB爱好者论坛-LabFans.com

xiaowangzitobe · 2012-03-27, 19:01

clc;
clear;
i = sqrt(-1);
e0 = 2.25; e2 = 13.7; e = 1.6e-19; e_0 = 8.85e-12;
m = 9.1e-31; w = 2.36e15 ;
eSi = 13.7; n0 = 2e29; mopt = 0.18; tau_D = 1e-15; c = 3e8; ncr = 5e27;
neh = 1.6*ncr;
wp = sqrt(neh*e^2/(e_0*mopt*m));
e1 = 1+(eSi-1)*(1-neh/n0)-(wp^2/w^2)*(1/(1+i*(w*tau_D)^(-1)));
d = 1/sqrt((2*sqrt(e1*conj(e1))-(e1+conj(e1))));

给定以上的参数,求如下方程 z1的解.
tanh(i*(sqrt(e1 - z1))*d) - (sqrt(e1 - z1)/e1)*((sqrt(e0 - z1)/e0)+(sqrt(e2 - z1)/e2))/((sqrt(e1 - z1)/e1)^2+(sqrt(e0 - z1)/e0)*(sqrt(e2 - z1)/e2)

应该用什么函数才能得到多解?
多谢高手帮忙!!

2012-03-27, 19:01	#1
xiaowangzitobe 初级会员注册日期: 2012-03-27 年龄: 39 帖子: 1 声望力: 0	一元方程求多解 with complex number clc; clear; i = sqrt(-1); e0 = 2.25; e2 = 13.7; e = 1.6e-19; e_0 = 8.85e-12; m = 9.1e-31; w = 2.36e15 ; eSi = 13.7; n0 = 2e29; mopt = 0.18; tau_D = 1e-15; c = 3e8; ncr = 5e27; neh = 1.6ncr; wp = sqrt(nehe^2/(e_0moptm)); e1 = 1+(eSi-1)(1-neh/n0)-(wp^2/w^2)(1/(1+i(wtau_D)^(-1))); d = 1/sqrt((2sqrt(e1conj(e1))-(e1+conj(e1)))); 给定以上的参数,求如下方程 z1的解. tanh(i(sqrt(e1 - z1))d) - (sqrt(e1 - z1)/e1)((sqrt(e0 - z1)/e0)+(sqrt(e2 - z1)/e2))/((sqrt(e1 - z1)/e1)^2+(sqrt(e0 - z1)/e0)(sqrt(e2 - z1)/e2) 应该用什么函数才能得到多解? 多谢高手帮忙!!