| Labfans是一个针对大学生、工程师和科研工作者的技术社区。 | 论坛首页 | 联系我们(Contact Us) | 
![]()  | 
	
| 		
			
			 | 
		#1 | 
| 
			
			 初级会员 
			
			
			
			注册日期: 2008-03-22 
				
				年龄: 42 
				
					帖子: 8
				 
				
				
				声望力: 0 ![]()  | 
	
	
	
		
		
			
			 
			
			每次运行下面的这段代码,系统都会提示:下标为非正整数。可我看了半天也没找出来。大家帮忙看看 
		
		
		
		
		
		
			%Subroutine to apply Mr.Mur's absorbing boundary conditions function c=mr_mur(ezs,ezs1,ezs2,nx1,ny1,nx,ny,c1,c3) %corners are done with first order ezs(1,1)=ezs1(2,1)+c1*(ezs(2,1)-ezs1(1,1)); ezs(1,ny)=ezs1(2,ny)+c1*(ezs(2,ny)-ezs1(1,ny)); ezs(nx,1)=ezs1(nx,1)+c1*(ezs(nx1,1)-ezs1(nx,1)); ezs(nx,ny)=ezs1(nx1,ny)+c1*(ezs(nx1,ny)-ezs1(nx,ny)); %second order elsewhere for j=2:ny1 ezs(1,j)=ezs2(2,j)+c1*(ezs(2,j)-ezs2(1,j))... -c3*(hxs(1,j+1)-hxs(1,j-1)+hxs(2,j+1)-hxs(2,j-1)); end for j=2:ny1 ezs(nx,j)=ezs2(nx1,j)+c1*(ezs(nx1,j)-ezs2(nx,j))... -c3*(hxs(nx,j+1)+hxs(nx1,j+1)-hxs(nx,j-1)-hxs(nx1,j-1)); end for i=2:nx1 ezs(i,1)=-ezs2(i,2)+c1*(ezs(i,2)-ezs2(i,1))... +c3*(hys(i+1,2)+hys(i+1,1)-hys(i-1,2)-hys(i-1,1)); end for i=2:nx1 ezs(i,ny)=ezs2(i,ny1)+c1*(ezs2(i,ny1)-ezs(i,ny1))... +c3*(hys(i+1,ny)+hys(i+1,ny1)-hys(i-1,ny)-hys(i-1,ny1)); end for i=1:nx for j=1:ny ezs2(i,j)=ezs1(i,j); ezs1(i,j)=ezs(i,j); end end     c=ezs; 其中:ezs(i,j)=ezs1(i,j)=ezs2(i,j) , nx=ny=256, nx1=nx-1 , ny1=ny-1 , c1,c3是常数 
				__________________ 
		
		
		
		
	:lol: :lol: :lol:  | 
| 
		 | 
	
	
	
		
		
		
		
			 
		
		
		
		
		
		
		
			
		
		
		
	 |