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yinjiangming · 2008-05-04, 15:29

[a b c]=solve('1000=b/(1+(b/a-1)*exp(c*4.75))','1626=b/(1+(b/a-1)*exp(c*5.5))','3300=b/(1+(b/a-1)*exp(c*6.6))')
先这样求出大概解为
a=45
b=149732
c=-0.6538
然后以这个为初值进行计算

2008-05-04, 15:29	#3
yinjiangming 初级会员注册日期: 2008-04-23 年龄: 48 帖子: 10 声望力: 18	[a b c]=solve('1000=b/(1+(b/a-1)exp(c4.75))','1626=b/(1+(b/a-1)exp(c5.5))','3300=b/(1+(b/a-1)exp(c6.6))') 先这样求出大概解为 a=45 b=149732 c=-0.6538 然后以这个为初值进行计算