关于二元一次指数方程组的求解
			 
			 
			
		
		
		
			
			程序如下: 
syms x y m n  
 f2=exp(-1/20*x-1/20*y); 
 m2=int(int(f2,y,n+(m-x)/0.5,inf),x,0,m) 
 m3=int(int(f2,x,m,m+(n-y)/0.4),y,0,n) 
 m4=int(int(f2,x,m+(n-y)/0.4,inf),y,0,n) 
 m5=int(int(f2,y,n,n+(m-x)/0.5),x,0,m) 
[m,n]=solve('70*exp(-m/20)+30*(exp(-m/20)-1)-36*20+38/20*m2-14/20*m3=0','65*exp(-m/20)+28*(exp(-m/20)-1)-36*20+35/20*m4-19/20*m5=0','m','n') 
 
计算结果如下: 
m2 = 
  
(400*exp(m/20) - 400)/exp(m/10 + n/20) 
  
  
m3 = 
  
400/exp(m/20) + 800/(3*exp(m/20 + n/8)) - 2000/(3*exp(m/20 + n/20)) 
  
  
m4 = 
  
((800*exp((3*n)/40))/3 - 800/3)/exp(m/20 + n/8) 
  
  
m5 = 
  
400/exp(n/20) + 400/exp(m/10 + n/20) - 800/exp(m/20 + n/20) 
  
  
m = 
  
z 
  
  
n = 
  
z1 
请问z和z1是什么?
		 
		
		
		
		
		
		
		
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