matlab周期信号傅里叶展开求助
			 
			 
			
		
		
		
			
			%周期信号的傅里叶级数展开; 
display('输入傅里叶级数展开的项数m:'); 
m=input('m='); 
t=-2*pi:0.01:pi; 
n=round(length(t)/4); 
f=[ones(n,1);-1*ones(n,1);ones(n,1);-1*ones(n+1,1)]; 
y=zeros(m+1,max(size(t))); 
y(m+1,:)=f';提示有错,我也不知道这是什么意思,请问能解释下吗? 
figure(1); 
plot(t/pi,y(m+1,:)); 
grid; 
axis([-2,2,-1.5,1.5]) 
title('周期方波') 
xlabel('单位:pi','Fontsize,8'); 
x=zeros(size(t)); 
kk='1'; 
for k=1:2:2*m-1 
    pause; 
    x=x+sin(k*t)/k; 
    y((k+1)/2,:)=4/pi*x; 
    plot(t/pi,y(m+1,:)); 
    hold on; 
    plot(t/pi,y((k+1)/2,:)); 
    hold off; 
    grid; 
    axis([-2,2,-1.5,1.5]) 
    title(stract('第',kk,'次谐波叠加')); 
    xlabel(' 单位:pi','Fontsize,8'); 
    kk=stract(kk,'、',num2str(k+2)); 
end 
pause; 
plot(t/pi,y(m+1,:)); 
grid; 
axis([-2 2 -1.5 1.5]); 
title('各次谐波叠加') 
xlabel('单位:pi','Fontsize',8);:mad: 
%end
		 
		
		
		
		
		
		
		
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