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cfchenchen · 2009-06-22, 14:47

结果:
y1 =

(3*x^2+1)/(x^3+x+3)

y2 =

6*x/(x^3+x+3)-(3*x^2+1)^2/(x^3+x+3)^2

2009-06-22, 14:47	#3
cfchenchen 初级会员注册日期: 2009-06-20 住址: 学校年龄: 38 帖子: 24 声望力: 16	回复: 请教绘图问题结果: y1 = (3x^2+1)/(x^3+x+3) y2 = 6x/(x^3+x+3)-(3*x^2+1)^2/(x^3+x+3)^2