回复: matlab曲线拟合
			 
			 
			
		
		
		
			
			对于前两个问题,结果为: 
 
fx1=b(1)*b(2)*exp(b(3)*x)./(b(2)-b(1)+b(1)*exp(b(3)*x)); 
 
SSy =       92.859 
b =[0.47763211, 7.8235271, 0.034831922] 
RSS = 1.697449365 
MSe =      0.14145 
R^2 =      0.98172 
 
fx2=b(4)*b(1)*b(2)*exp(b(3)*(x-25))./(b(2)-b(1)+b(1)*exp(b(3)*(x-25))); 
 
SSy =   19.657 
b =[0.013595125, 3.3361276, 0.056854978, 1.1402108] 
RSS = 0.07766445926 
MSe =    0.0070604 
R^2 =   0.99605 
 
第3个问题 
fx3=b(5)-(b(1)*b(2)*exp(b(3)*x))./(b(7)*(b(2)-b(1)+b(1)*exp(b(3)*x)))+b(1)/b(7)-b(2)*b(6)/b(3)*log((b(1)-b(2)-b(1)*exp(b(3)*x))/b(2)); 
的结果(时间关系,不及验证)似为: 
b=[143.6218337, -0.1206944498, 0.004223585525, 5845.510552, 4567.540506, -102.7556157, 0.009232308418]
		 
		
		
		
		
		
		
		
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