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slgu · 2009-04-22, 19:53

fy=b(1)./(1+b(2)*x.^2+b(3)*x.^4+b(4)*exp(b(5)*x.^2));
b =[ -0.10245748, -0.015258002, 0.0000012473027, -4.589731, -0.028092274]
RSS =0.0009084860045
MSe = 1.0946e-005
R^2 = 0.99417

2009-04-22, 19:53	#2
slgu 高级会员注册日期: 2007-06-24 年龄: 70 帖子: 188 声望力: 21	回复: 急求教：曲线拟合 fy=b(1)./(1+b(2)x.^2+b(3)x.^4+b(4)exp(b(5)x.^2)); b =[ -0.10245748, -0.015258002, 0.0000012473027, -4.589731, -0.028092274] RSS =0.0009084860045 MSe = 1.0946e-005 R^2 = 0.99417