回复: 就是离散数学中可闭包问题
function b = qiupf(x)
% 函数名 qiupf = 求矩阵的平方;
% A^2 = A*A 是取大取小算法;
[m, n] = size(x);
if m ~= n
disp('输入的矩阵不是方阵');
return
end
for i = 1:n
for j = 1:n
for k = 1:n
b(k) = min(x(i,k),x(k,j));
end
xsquare(i,j) = max(b);
end
end
b = xsquare;
|