poster
2019-12-14, 20:13
我只想跟踪灰色图像中的边界。我遇到了两次区域边界问题。我如何只获得一个边界并位于边缘像素的中心。在下面的示例中，我得到了两个区域4、30。但是我只需要（4）。要获得该图像需要进行哪些图像预处理。
示例：请参阅第4，30区
BW = imread('blobs.png'); = bwboundaries(BW); figure, imshow(BW); hold on; colors=['b' 'g' 'r' 'c' 'm' 'y']; for k=1:length(B) boundary = B{k}; cidx = mod(k,length(colors))+1; plot(boundary(:,2), boundary(:,1),... colors(cidx),'LineWidth',2); %randomize text position for better visibility rndRow = ceil(length(boundary)/(mod(rand*k,7)+1)); col = boundary(rndRow,2); row = boundary(rndRow,1); h = text(col+1, row-1, num2str(L(row,col))); set(h,'Color',colors(cidx),... 'FontSize',14,'FontWeight','bold'); end figure; spy(A);
[B]回答：
使用noholes -option调用bwboundaries 。这消除了对象的内部边界。
换一种说法：
[B,L,N,A] = bwboundaries(BW,8,'noholes'); %# 8 is for 8-connected pixels
更多&回答... (https://stackoverflow.com/questions/4706591)
示例：请参阅第4，30区
BW = imread('blobs.png'); = bwboundaries(BW); figure, imshow(BW); hold on; colors=['b' 'g' 'r' 'c' 'm' 'y']; for k=1:length(B) boundary = B{k}; cidx = mod(k,length(colors))+1; plot(boundary(:,2), boundary(:,1),... colors(cidx),'LineWidth',2); %randomize text position for better visibility rndRow = ceil(length(boundary)/(mod(rand*k,7)+1)); col = boundary(rndRow,2); row = boundary(rndRow,1); h = text(col+1, row-1, num2str(L(row,col))); set(h,'Color',colors(cidx),... 'FontSize',14,'FontWeight','bold'); end figure; spy(A);
[B]回答：
使用noholes -option调用bwboundaries 。这消除了对象的内部边界。
换一种说法：
[B,L,N,A] = bwboundaries(BW,8,'noholes'); %# 8 is for 8-connected pixels
更多&回答... (https://stackoverflow.com/questions/4706591)